【100分】请教SQL行数据中分别以","的数据单独转换成一行数据如何转？
表数据：
F1 F2
a 1,2,5
b 1,3
c 3,5
要得到
F1 F2
a 1
a 2
a 5
b 1
b 3
c 3
c 5
就是把后面的F2中每个值变一行数据出来
请各位大侠多多指点,thanks.
[解决办法]
DECLARE @tb Table(
CompanyID INT,
CompanyCodes VARCHAR(100)
)
insert into @tb select 1,'1|2'
union all select 2,'1|2|3'
union all select 3,'1|2|3|4'
union all select 4,'1|2|3|4|5'
;WITH cte AS (
SELECT
CompanyID,
CAST('<i>' + REPLACE(CompanyCodes, '|', '</i><i>') + '</i>' AS XML) AS CompanyCodes
FROM @tb
)
SELECT
CompanyID,
x.i.value('.', 'VARCHAR(10)') AS CompanyCode
FROM cte
CROSS APPLY CompanyCodes.nodes('i') x(i)
刚刚看完的一个案例。
[解决办法]
DECLARE @tb Table(
F1 varchar(12),
F2 VARCHAR(100)
)
insert into @tb select 'a','1,2,5'
union all select 'b','1,3'
union all select 'c','3,5'
;WITH cte AS (
SELECT
F1,
CAST('<i>' + REPLACE(F2, ',', '</i><i>') + '</i>' AS XML) AS F2
FROM @tb
)
SELECT
F1,
x.i.value('.', 'VARCHAR(10)') AS F2
FROM cte
CROSS APPLY F2.nodes('i') x(i)
[解决办法]
3楼正解!
[解决办法]
DECLARE @tb Table( CompanyID INT, CompanyCodes VARCHAR(100) ) insert into @tb select 1,'1|2' union all select 2,'1|2|3' union all select 3,'1|2|3|4'union all select 4,'1|2|3|4|5'select a.CompanyID, CompanyCodes = substring(a.CompanyCodes,b.number,charindex('|',a.CompanyCodes+'|',b.number)-b.number)from @tb a join master..spt_values b on b.[type] = 'p' and b.number between 0 and len(a.CompanyCodes) and substring('|'+a.CompanyCodes,b.number,1) = '|'/****************CompanyID CompanyCodes----------- ----------------------------------------------------------------1 11 22 12 22 33 13 23 33 44 14 24 34 44 5(14 行受影响)
[解决办法]
DECLARE @tb Table(
F1 varchar(12),
F2 VARCHAR(100)
)
insert into @tb select 'a','1,2,5'
union all select 'b','1,3'
union all select 'c','3,5'
select a.F1,b.vx
from
(select F1,cast('<root><v>'+REPLACE(F2,',','</v><v>')+'</v></root>' as xml) as x from @tb) a
outer apply(
select vx=N.v.value('.','varchar(100)') from a.x.nodes('/root/v') N(v)
) b
[解决办法]
凑个热闹
create table tb(F1 char(1),F2 varchar(10))insert into tb select 'a','1,2,5' union select 'b','1,3' union select 'c','3,5' create function f(@str varchar(20))returns @t table (F varchar(2))asbegin set @str=@str+',' while CHARINDEX(',',@str)>0 begin insert into @t select left(@str,CHARINDEX(',',@str)-1) set @str=right(@str,len(@str)-CHARINDEX(',',@str)) end return endselect a.F1,b.* from tb across apply f(a.F2)b/*F1 F---- ----a 1a 2a 5b 1b 3c 3c 5
[解决办法]
2005:
create table tb(F1 varchar(10),F2 varchar(20))insert into tb select 'a','1,2,5'insert into tb select 'b','1,3'insert into tb select 'c','3,5'goselect a.F1,substring(a.F2,b.number,charindex(',',a.F2+',',b.number+1)-b.number)F2from tb a,master..spt_values bwhere b.type='p' and b.number<=len(a.F2) and substring(a.F2,b.number,1)<>',' and substring(','+a.F2,b.number,1)=','/*F1 F2---------- --------------------a 1a 2a 5b 1b 3c 3c 5(7 行受影响)*/godrop table tb
[解决办法]
sql真是无所不能啊。
[解决办法]
--分拆列值--原著：邹建--改编：爱新觉罗.毓华(十八年风雨,守得冰山雪莲花开) 2007-12-16 广东深圳/*有表tb, 如下: id value ----------- ----------- 1 aa,bb 2 aaa,bbb,ccc */--欲按id,分拆value列, 分拆后结果如下: /*id value ----------- -------- 1 aa 1 bb 2 aaa 2 bbb 2 ccc */--1. 旧的解决方法(sql server 2000) select top 8000 id = identity(int, 1, 1) into # from syscolumns a, syscolumns b select A.id, substring(A.[values], B.id, charindex(',', A.[values] + ',', B.id) - B.id) from tb A, # B where substring(',' + A.[values], B.id, 1) = ',' drop table # --2. 新的解决方法(sql server 2005) create table tb(id int,value varchar(30)) insert into tb values(1,'aa,bb') insert into tb values(2,'aaa,bbb,ccc') go select A.id, B.value from( select id, [value] = convert(xml,' <root> <v>' + replace([value], ',', ' </v> <v>') + ' </v> </root>') from tb )A outer apply( select value = N.v.value('.', 'varchar(100)') from A.[value].nodes('/root/v') N(v) )B drop table tb /* id value ----------- ------------------------------ 1 aa 1 bb 2 aaa 2 bbb 2 ccc (5 行受影响) */
[解决办法]
CREATE Table #tb( F1 varchar(12), F2 VARCHAR(100) ) insert into #tb select 'a','1,2,5' union all select 'b','1,3' union all select 'c','3,5'--方法一：SELECT A.F1,B.F2FROM( SELECT F1, F2 = CONVERT(xml,'<root><v>' + REPLACE(F2, ',', '</v><v>') + '</v></root>') FROM #tb)AOUTER APPLY( SELECT F2 = N.v.value('.', 'varchar(100)') FROM A.F2.nodes('/root/v') N(v))Bgo--方法二：select a.F1,F2=SUBSTRING(a.F2,b.number,CHARINDEX(',',a.F2+',',b.number)-b.number)from #tb a join master..spt_values b on b.type='p' and b.number <=len(a.F2)where CHARINDEX(',',','+a.F2,b.number)=b.number结果为：F1 F2a 1a 2a 5b 1b 3c 3c 5
[解决办法]
/****************************************************************************************************************************************************** 合并分拆表数据 整理人：中国风(Roy) 日期:2008.06.06 ******************************************************************************************************************************************************/ --> --> (Roy)生成測試數據 if not object_id('Tab') is null drop table Tab Go Create table Tab([Col1] int,[Col2] nvarchar(1)) Insert Tab select 1,N'a' union all select 1,N'b' union all select 1,N'c' union all select 2,N'd' union all select 2,N'e' union all select 3,N'f' Go 合并表: SQL2000用函数: go if object_id('F_Str') is not null drop function F_Str go create function F_Str(@Col1 int) returns nvarchar(100) as begin declare @S nvarchar(100) select @S=isnull(@S+',','')+Col2 from Tab where Col1=@Col1 return @S end go Select distinct Col1,Col2=dbo.F_Str(Col1) from Tab go SQL2005用XML: 方法1: select a.Col1,Col2=stuff(b.Col2.value('/R[1]','nvarchar(max)'),1,1,'') from (select distinct COl1 from Tab) a Cross apply (select COl2=(select N','+Col2 from Tab where Col1=a.COl1 For XML PATH(''), ROOT('R'), TYPE))b 方法2: select a.Col1,COl2=replace(b.Col2.value('/Tab[1]','nvarchar(max)'),char(44)+char(32),char(44)) from (select distinct COl1 from Tab) a cross apply (select Col2=(select COl2 from Tab where COl1=a.COl1 FOR XML AUTO, TYPE) .query(' <Tab> {for $i in /Tab[position() <last()]/@COl2 return concat(string($i),",")} {concat("",string(/Tab[last()]/@COl2))} </Tab>') )b SQL05用CTE: ;with roy as(select Col1,Col2,row=row_number()over(partition by COl1 order by COl1) from Tab) ,Roy2 as (select COl1,cast(COl2 as nvarchar(100))COl2,row from Roy where row=1 union all select a.Col1,cast(b.COl2+','+a.COl2 as nvarchar(100)),a.row from Roy a join Roy2 b on a.COl1=b.COl1 and a.row=b.row+1) select Col1,Col2 from Roy2 a where row=(select max(row) from roy where Col1=a.COl1) order by Col1 option (MAXRECURSION 0) 生成结果: /* Col1 COl2 ----------- ------------ 1 a,b,c 2 d,e 3 f (3 行受影响) */ --参考拆分表:--> --> (Roy)生成測試數據 if not object_id('Tab') is null drop table TabGoCreate table Tab([Col1] int,[COl2] nvarchar(5))Insert Tabselect 1,N'a,b,c' union allselect 2,N'd,e' union allselect 3,N'f'Go--SQL2000用辅助表:if object_id('Tempdb..#Num') is not null drop table #Numgoselect top 100 ID=Identity(int,1,1) into #Num from syscolumns a,syscolumns bSelect a.Col1,COl2=substring(a.Col2,b.ID,charindex(',',a.Col2+',',b.ID)-b.ID) from Tab a,#Num bwhere charindex(',',','+a.Col2,b.ID)=b.ID --也可用 substring(','+a.COl2,b.ID,1)=','--2000不使用辅助表Select a.Col1,COl2=substring(a.Col2,b.number,charindex(',',a.Col2+',',b.number)-b.number) from Tab a join master..spt_values b ON B.type='p' AND B.number BETWEEN 1 AND LEN(A.col2)where substring(','+a.COl2,b.number,1)=','SQL2005用Xml:select a.COl1,b.Col2from (select Col1,COl2=convert(xml,'<root><v>'+replace(COl2,',','</v><v>')+'</v></root>') from Tab)aouter apply (select Col2=C.v.value('.','nvarchar(100)') from a.COl2.nodes('/root/v')C(v))bSQL05用CTE:;with roy as (select Col1,COl2=cast(left(Col2,charindex(',',Col2+',')-1) as nvarchar(100)),Split=cast(stuff(COl2+',',1,charindex(',',Col2+','),'') as nvarchar(100)) from Tabunion allselect Col1,COl2=cast(left(Split,charindex(',',Split)-1) as nvarchar(100)),Split= cast(stuff(Split,1,charindex(',',Split),'') as nvarchar(100)) from Roy where split>'')select COl1,COl2 from roy order by COl1 option (MAXRECURSION 0)生成结果:/*Col1 COl2----------- -----1 a1 b1 c2 d2 e3 f*/