求高手帮小弟我解决一个SQL server语句的有关问题！

求高手帮我解决一个SQL server语句的问题！！！
我如果想查询本月的所有支出，在SQL server中用
select SUM(price) as sumpayM from pay where DATEPART(MM,time)
=DATEPART(MM,GETDATE()) and DATEPART(YY,time)
=DATEPART(YY,GETDATE()) and userid=1;就可了。
但如果我想查询本月的每天所有支出，应该怎么写啊！
我有这么一段代码，不过是oracle数据库的语句：
//查询本月支出情况
public List getPayByM(Connection con,Long userId)throws SQLException{
Statement st = con.createStatement();
int s = this.GetDay(con);
List list = new ArrayList();
  String a ="";  
  for(int i=0;i<s;i++){
  int z = i+1;
  if(i==(s-1)){
  a+="sum(decode(extract(day from b.times),"+(i+1)+",b.price,0)) as a"+(i+1);
  }else{
  a+="sum(decode(extract(day from b.times),"+(i+1)+",b.price,0)) as a"+(i+1)+" , ";
  }
  }
  String sql ="SELECT "+a+" FROM pay b where b.userid="+userId+" and extract(month from b.times)=07";
  ResultSet rs1 = st.executeQuery(sql);
  if(rs1.next()){
  for(int i=0;i<s;i++){
  list.add(rs1.getInt("a"+(i+1)));
  }
}
return list;

}

[解决办法]

SQL code

select SUM(price) as sumpayD from pay where DATEPART(MM,time)=DATEPART(MM,GETDATE()) and DATEPART(YY,time)=DATEPART(YY,GETDATE()) and userid=1group by cast(time as varchar(10))
[解决办法]
SQL code
select convert(varchar(10),time,120) D,SUM(price) as sumpayD from pay where DATEPART(MM,time)=DATEPART(MM,GETDATE()) and DATEPART(YY,time)=DATEPART(YY,GETDATE()) and userid=1group by convert(varchar(10),time,120)
[解决办法]
SQL code
select  convert(varchar(10),time,120),d,sum(price) as sumpayDfrom  paywhere  datediff(mm,time,getdate())=0and  userid=1group by  convert(varchar(10),time,120),d
[解决办法]
SQL code
select SUM(price) as sumpayM from pay where DATEPART(MM,time)=DATEPART(MM,GETDATE()) and DATEPART(YY,time)=DATEPART(YY,GETDATE()) and userid=1 group by convert(varchar(10),time,120)
[解决办法]
--多分析一下问题，往往分析能帮你发现新的思路
select
 convert(varchar(10),time,120),d,sum(price) as sumpayD
from
 pay
where
 datediff(mm,time,getdate())=0
and
 userid=1
group by
 convert(varchar(10),time,120),d