简单问题，马上散分，显示重复行
ID Title num
1 aa 1
2 bb 3
3 cc 4
4 dd 3
5 ee 4
6 ff 1
我想实现查找后显示num唯一id和title，求助
[解决办法]
select a.* from tb a,
(select num,min(id) as id from tb group by num) b
where a.num = b.num and a.id = b.id
[解决办法]
create table T(ID int, Title varchar(10), num int)
insert T select 1, 'aa ', 1
union all select 2, 'bb ', 3
union all select 3, 'cc ', 4
union all select 4, 'dd ', 3
union all select 5, 'ee ', 4
union all select 6, 'ff ', 1
select * from T as tmp
where not exists(select 1 from T where num=tmp.num and ID> tmp.ID)
--result
ID Title num
----------- ---------- -----------
4 dd 3
5 ee 4
6 ff 1
(3 row(s) affected)
