求助,值班代码怎么写
最近在做单位的网站,基础很薄弱,很多东西都是边看书边百度摸索着做的
最近想要实现在主页上显示每天的值班人员,四天轮一次。
我写的代码如下。
<?php
$zbb0=array("张三","李四","王五")
$zbb1=array("张三1","李四1","王五1")
$zbb2=array("张三2","李四2","王五2")
$zbb3=array("张三3","李四3","王五3")
$date_time=getdate(time));
$yday=$date_time["yday"];
if ($yday%4==0){
echo "$zbb0";}
if ($yday%4==1){
echo "$zbb1";}
if ($yday%4==2){
echo "$zbb2";}
if ($yday%4==3){
echo "$zbb3";}
?>
大概意思就是获取当前日期是今年的第几天,再除以四得出余数,根据余数的数值显示相应的人员
[解决办法]
$zbb0=array("张三","李四","王五");
$zbb1=array("张三1","李四1","王五1");
$zbb2=array("张三2","李四2","王五2");
$zbb3=array("张三3","李四3","王五3");
$date_time=getdate(time());
$yday=$date_time["yday"];
$day=$yday%4; //余数
$zb='zbb'.$day; //是哪天的变量
$zbb=$$zb;
print_r($zbb);
[解决办法]
<?$zb=array(1=>array("张三","李四","王五"),array("张三1","李四1","王五1"),array("张三2","李四2","王五2"),array("张三3","李四3","王五3")); $today=date("N"); switch ($today%4){ case 1: print_r($zb[1]); break; case 2: print_r($zb[2]); break; case 3: print_r($zb[3]); break; case 4: print_r($zb[3]); break; }?>
[解决办法]
$zbb = array(
array("张三","李四","王五"),
array("张三1","李四1","王五1"),
array("张三2","李四2","王五2"),
array("张三3","李四3","王五3"),
);
print_r($zbb[date('z')%4]);
或
echo join(',', $zbb[date('z')%4]);