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列转逗号分隔的形式解决方法

2012-03-09 
列转逗号分隔的形式源表goodsid sheetid100110001100110002100210003100310004100410004100410005想要变成

列转逗号分隔的形式
源表
goodsid sheetid 

1001 10001
1001 10002
1002 10003
1003 10004
1004 10004
1004 10005

想要变成group by goodsid的形式

goodsid sheeetid
1001 10001,10002
1002 10003
1003 10004
1004 10004,10005

数据无限多,goodsid有重复,sheetid有重复
我试过declare sql varchar(8000)
set @sql=''
select @sql=@sql+sheetid+',' from table 
where goodsid='1001'

这个只能取出一列的数据来,不能分组取

请各位高手指点




[解决办法]

SQL code
create table tb(goodsid varchar(10),sheetid varchar(10))insert into tb select '1001','10001'insert into tb select '1001','10002'insert into tb select '1002','10003'insert into tb select '1003','10004'insert into tb select '1004','10004'insert into tb select '1004','10005'goselect goodsid,stuff((select ','+sheetid from tb where goodsid=a.goodsid for xml path('')),1,1,'')sheetid from tb a group by goodsid/*goodsid    sheetid---------- --------------------------------------------------------------------------1001       10001,100021002       100031003       100041004       10004,10005(4 行受影响)*/godrop table tb
[解决办法]
參照方法
SQL code
-> --> (Roy)生成測試數據 if not object_id('Tab') is null    drop table TabGoCreate table Tab([Col1] int,[Col2] nvarchar(1))Insert Tabselect 1,N'a' union allselect 1,N'b' union allselect 1,N'c' union allselect 2,N'd' union allselect 2,N'e' union allselect 3,N'f'Go合并表:SQL2000用函数:goif object_id('F_Str') is not null    drop function F_Strgocreate function F_Str(@Col1 int)returns nvarchar(100)asbegin    declare @S nvarchar(100)    select @S=isnull(@S+',','')+Col2 from Tab where Col1=@Col1    return @SendgoSelect distinct Col1,Col2=dbo.F_Str(Col1) from TabgoSQL2005用XML:方法1:select     a.Col1,Col2=stuff(b.Col2.value('/R[1]','nvarchar(max)'),1,1,'')from     (select distinct COl1 from Tab) aCross apply    (select COl2=(select N','+Col2 from Tab where Col1=a.COl1 For XML PATH(''), ROOT('R'), TYPE))b方法2:select     a.Col1,COl2=replace(b.Col2.value('/Tab[1]','nvarchar(max)'),char(44)+char(32),char(44))from     (select distinct COl1 from Tab) across apply    (select Col2=(select COl2 from Tab  where COl1=a.COl1 FOR XML AUTO, TYPE)                .query('<Tab>                {for $i in /Tab[position()<last()]/@COl2 return concat(string($i),",")}                {concat("",string(/Tab[last()]/@COl2))}                </Tab>')                )bSQL05用CTE:;with roy as(select Col1,Col2,row=row_number()over(partition by COl1 order by COl1) from Tab),Roy2 as(select COl1,cast(COl2 as nvarchar(100))COl2,row from Roy where row=1 union all select a.Col1,cast(b.COl2+','+a.COl2 as nvarchar(100)),a.row from Roy a join Roy2 b on a.COl1=b.COl1 and a.row=b.row+1)select Col1,Col2 from Roy2 a where row=(select max(row) from roy where Col1=a.COl1) order by Col1 option (MAXRECURSION 0)生成结果:/*Col1        COl2----------- ------------1           a,b,c2           d,e3           f(3 行受影响)*/
[解决办法]
SQL code
use Tempdbgo--> -->  if not object_id(N'T') is null    drop table TGoCreate table T([goodsid] int,[sheetid] int)Insert Tselect 1001,10001 union allselect 1001,10002 union allselect 1002,10003 union allselect 1003,10004 union allselect 1004,10004 union allselect 1004,10005Goselect     a.[goodsid],[sheetid]=replace(b.[sheetid].value('/T[1]','nvarchar(max)'),char(44)+char(32),char(44))from     (select distinct [goodsid] from T) across apply    (select [sheetid]=(select [sheetid] from T  where [goodsid]=a.[goodsid] FOR XML AUTO, TYPE)                .query('<T>                {for $i in /T[position()<last()]/@sheetid return concat(string($i),",")}                {concat("",string(/T[last()]/@sheetid))}                </T>')                )b/*goodsid    sheetid1001    10001,100021002    100031003    100041004    10004,10005*/ 


[解决办法]

探讨

忘了说了 sql2000

[解决办法]
SQL code
合并列值 --*******************************************************************************************表结构,数据如下: id    value ----- ------ 1    aa 1    bb 2    aaa 2    bbb 2    ccc 需要得到结果: id    values ------ ----------- 1      aa,bb 2      aaa,bbb,ccc 即:group by id, 求 value 的和(字符串相加) 1. 旧的解决方法(在sql server 2000中只能用函数解决。) --=============================================================================create table tb(id int, value varchar(10)) insert into tb values(1, 'aa') insert into tb values(1, 'bb') insert into tb values(2, 'aaa') insert into tb values(2, 'bbb') insert into tb values(2, 'ccc') go --1. 创建处理函数 CREATE FUNCTION dbo.f_strUnite(@id int) RETURNS varchar(8000) AS BEGIN     DECLARE @str varchar(8000)     SET @str = ''     SELECT @str = @str + ',' + value FROM tb WHERE id=@id     RETURN STUFF(@str, 1, 1, '') END GO -- 调用函数 SELECt id, value = dbo.f_strUnite(id) FROM tb GROUP BY id drop table tb drop function dbo.f_strUnite go/* id          value      ----------- ----------- 1          aa,bb 2          aaa,bbb,ccc (所影响的行数为 2 行) */ --===================================================================================2. 新的解决方法(在sql server 2005中用OUTER APPLY等解决。) create table tb(id int, value varchar(10)) insert into tb values(1, 'aa') insert into tb values(1, 'bb') insert into tb values(2, 'aaa') insert into tb values(2, 'bbb') insert into tb values(2, 'ccc') go -- 查询处理 SELECT * FROM(SELECT DISTINCT id FROM tb)A OUTER APPLY(         SELECT [values]= STUFF(REPLACE(REPLACE(             (                 SELECT value FROM tb N                 WHERE id = A.id                 FOR XML AUTO             ), ' <N value="', ','), '"/>', ''), 1, 1, '') )N drop table tb /* id          values ----------- ----------- 1          aa,bb 2          aaa,bbb,ccc (2 行受影响) */ --SQL2005中的方法2 create table tb(id int, value varchar(10)) insert into tb values(1, 'aa') insert into tb values(1, 'bb') insert into tb values(2, 'aaa') insert into tb values(2, 'bbb') insert into tb values(2, 'ccc') go select id, [values]=stuff((select ','+[value] from tb t where id=tb.id for xml path('')), 1, 1, '') from tb group by id /* id          values ----------- -------------------- 1          aa,bb 2          aaa,bbb,ccc (2 row(s) affected) */ drop table tb /*标题:分拆列值1作者:爱新觉罗.毓华(十八年风雨,守得冰山雪莲花开)时间:2008-11-20地点:广东深圳描述有表tb, 如下:id          value----------- -----------1           aa,bb2           aaa,bbb,ccc欲按id,分拆value列, 分拆后结果如下:id          value----------- --------1           aa1           bb2           aaa2           bbb2           ccc*/--1. 旧的解决方法(sql server 2000)SELECT TOP 8000 id = IDENTITY(int, 1, 1) INTO # FROM syscolumns a, syscolumns b SELECT A.id, value = SUBSTRING(A.[value], B.id, CHARINDEX(',', A.[value] + ',', B.id) - B.id)FROM tb A, # BWHERE SUBSTRING(',' + A.[value], B.id, 1) = ','DROP TABLE #--2. 新的解决方法(sql server 2005) create table tb(id int,value varchar(30))insert into tb values(1,'aa,bb')insert into tb values(2,'aaa,bbb,ccc')goSELECT A.id, B.valueFROM(    SELECT id, [value] = CONVERT(xml,'<root><v>' + REPLACE([value], ',', '</v><v>') + '</v></root>') FROM tb)AOUTER APPLY(    SELECT value = N.v.value('.', 'varchar(100)') FROM A.[value].nodes('/root/v') N(v))BDROP TABLE tb/*id          value----------- ------------------------------1           aa1           bb2           aaa2           bbb2           ccc(5 行受影响)*/
[解决办法]
SQL code
--sql server 2005写法,要是2000就用自定义函数吧if object_id('tb','U') is not null   drop table tbgocreate table tb( goodsid int, sheetid int)goinsert into tbselect 1001,10001 union allselect 1001,10002 union allselect 1002,10003 union allselect 1003,10004 union allselect 1004,10004 union allselect 1004,10005goselect goodsid,sheeetid=stuff((select ','+cast(sheetid as varchar) from tb where goodsid=a.goodsid for xml path('')),1,1,'') from tb a group by goodsidgo/*goodsid     sheeetid----------- ----------------------------------------------------------------------------------------------------------------1001        10001,100021002        100031003        100041004        10004,10005(4 行受影响)*/ 


[解决办法]

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多谢 中国风 和小f 和qingtian

请问你们怎么这么厉害?

怎么学的啊

能不能给介绍点教材或者实例啊

我现在是基本的语句和语法会写,这些变化性很强的东西完全没有思路

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