C# 定义dll中的函数
在C++中的2个函数为
HANDLE OpenFile(char *FileName, int* Num)
BOOL Play(HANDLE Handle, HWND W1, HWND W2, HWND W3, HWND W4 )
如何定义在C#中?
[DllImport( "text.dll ", EntryPoint= "OpenFile ",CharSet=CharSet.Auto,CallingConvention=CallingConvention.Winapi)]
public static extern int OpenFile(ref char FileName,ref short iWndNum);
[DllImport(( "text.dll ", EntryPoint= "Play ",CharSet=CharSet.Auto,CallingConvention=CallingConvention.Winapi)]
public static extern bool Play(Int32 DecodeHandle,System.IntPtr Wnd1, System.IntPtr Wnd2, System.IntPtr Wnd3, System.IntPtr Wnd4 );
不知道对不对,请高人们指点!
谢谢!!!!!!!
[解决办法]
对的,在C#中,句柄一般都是用IntPtr,用unsigned int也行.建议用IntPtr
[解决办法]
主要看你的iWndNum参数，到底是单个传出参数，还是相应的数组参数，
如果是前者，可以如下：
[DllImport( "text.dll ", EntryPoint= "OpenFile ",CharSet=CharSet.Auto,CallingConvention=CallingConvention.Winapi)]
public static extern IntPtr OpenFile( StringBuilder FileName,ref short iWndNum);
calling:
StringBuilder sFileName = new StringBuilder(256);//init buffer
IntPtr hFile = OpenFile( sFileName, ref iWndNum );
否则，如下
[DllImport( "text.dll ", EntryPoint= "OpenFile ",CharSet=CharSet.Auto,CallingConvention=CallingConvention.Winapi)]
public static extern IntPtr OpenFile( StringBuilder FileName, short[] iWndNum);
calling:
StringBuilder sFileName = new StringBuilder(256);//init buffer
short[] iWndNum = new short[...];
IntPtr hFile = OpenFile( sFileName, iWndNum );
[解决办法]
好久不见，(愚翁)
