SQL语句 查找第 X 条 到第 X+N条 数据 怎么写
表中只有一个字段
表A
name
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张三
李四
王五
孙六
....
[解决办法]
取n到m行1. select top (n-m+1) * from tablename where id not in (select top n id from tablename order by id asc/*|desc*/) 2. select top m * into 临时表(或表变量) from tablename order by columnname -- 将top m笔插入到临时表 set rowcount n --只取n条结果select * from 表变量 order by columnname desc 3. select top n * from (select top m * from tablename order by columnname) a order by columnname desc 4.如果tablename里没有其他identity列,那么: 先生成一个序列,存储在一临时表中.select identity(int) id0,* into #temp from tablename 取n到m条的语句为: select * from #temp where id0 > =n and id0 <= m 如果你在执行select identity(int) id0,* into #temp from tablename这条语句的时候报错,那是因为你的DB中间的select into/bulkcopy属性没有打开要先执行: exec sp_dboption 你的DB名字,'select into/bulkcopy',true 5.如果表里有identity属性,那么简单: select * from tablename where identity_col between n and m 6.SQL2005开始.可以使用row_number() over()生成行号;with cte as( select id0=row_number() over(order by id),* from tablename)select * from cte where id0 between n to m
[解决办法]
[解决办法]
row_number() over()
[解决办法]
select * from (select *,row_number() over(order by getdate()) no from tb)twhere no between X and X+n