xml读取节点属性问题
初学，麻烦大家指导一下，xml文件如下
<?xml version= "1.0 " encoding= "utf-8 " ?>
<processes>
<process id= "1 " name= "请假流程 " >
<activity id= "start " name= "开始 " activityType= "1 ">
<state> 0 </state>
<people> qq </people>
<Transition number= "1 " joinType= "and ">
<nextActivity id= "A " />
</Transition >
</activity>
<activity id= "A " name= "部门审核 " activityType= "1 ">
<state> 0 </state>
<people> uu </people>
<Transition number= "1 " joinType= "and ">
<nextActivity id= "B " />
</Transition >
</activity>
<activity id= "End " name= "结束 " activityType= "1 ">
<state> 0 </state>
</activity>
</process>
</processes>
我想显示结果如下start-A-B ，start,A, B分别放在lable 里，用xmldocment ,没有查到相关用法，请教一下，有点着急！
protected void Page_Load(object sender, EventArgs e)
{
XmlDocument xdoc = new XmlDocument();
xdoc.Load = Xdoc.Load(Server.MapPath( "work.xml "));
???......
}
[解决办法]
string str =@ " <?xml version= " "1.0 " " encoding= " "utf-8 " " ?> <processes> <process id= " "1 " " name= " "请假流程 " " > <activity id= " "start " " name= " "开始 " " activityType= " "1 " "> <state> 0 </state> <people> qq </people> <Transition number= " "1 " " joinType= " "and " "> <nextActivity id= " "A " " /> </Transition > </activity> <activity id= " "A " " name= " "部门审核 " " activityType= " "1 " "> <state> 0 </state> <people> uu </people> <Transition number= " "1 " " joinType= " "and " "> <nextActivity id= " "B " " /> </Transition > </activity> <activity id= " "B " " name= " "人事部审核 " " activityType= " "1 " "> <state> 0 </state> <table> 人事部审核表 </table> <people> MM </people> <Transition number= " "1 " " joinType= " "and " "> <nextActivity id= " "End " " /> </Transition > </activity> </process> </processes> ";System.Xml.XmlDocument dom = new System.Xml.XmlDocument();dom.LoadXml(str);System.Xml.XmlNodeList nl = dom.SelectNodes( "//activity ");for(int i=0;i <nl.Count;i++){Response.Write(nl[i].Attributes[ "id "].Value + " <BR> ");}
