急，读取xml并比较，先谢谢了！
我要读取一xml文档内的所有记录，看看记录内是否有文件名为pathname1的记录
xml格式为
<?xml version= "1.0 " ?>
- <Team>
- <Backup>
<Filename> Event20070618100236001.avi </Filename>
<Time> 2006-2-8 11:12:31 </Time>
</Backup>
</Team>
急啊 ，谢谢了
[解决办法]
' 一下代码未经过测试
Imports System.Xml
Public Class Form1
Private Sub Form1_Load(ByVal sender As Object, ByVal e As System.EventArgs) Handles Me.Load
Dim x As New XmlDocument
x.Load( "a.xml ")
For Each el As XmlElement In x.GetElementsByTagName( "Backup ")
If el.GetElementsByTagName( "Filename ")(0).InnerText = "pathname1 " Then
MsgBox( "FOUND! ")
End If
Next
End Sub
End Class
[解决办法]
用XPath搜索吧！
[解决办法]
XmlDocument doc = new XmlDocument();
doc.Load(...);
string xpath = "/Backup[Filename= 'pathname1 '] ";
XmlNode node = doc.SelectSingleNode(xpath);
return node != null;
[解决办法]
如果是完全匹配
Imports System.Xml
Public Class Form1
Inherits System.Windows.Forms.Form
Private Sub Button1_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button1.Click
Dim xmlDoc As New XmlDocument
xmlDoc.Load( "C:\\XXX.xml ")
For Each x As XmlElement In xmlDoc.GetElementsByTagName( "Backup ")
If x.GetElementsByTagName( "Filename ")(0).InnerText = "pathname1 " Then
MsgBox( "Found ")
End If
Next
End Sub
End Class
