急送分！容易算法设计

急送分！！！！！！简单算法设计
template="我是${name}，我今年${age}"； 
name=***，age=**；存储在map中
设计一个算法把模板字符串中对应的替换：我是***，我今年**；
我正则表达式怎么做 请指教

[解决办法]
先把你要替换的内容,分别用数组存起来
然后用replaceAll(数组,要替换的内容),循环
[解决办法]

Java code

public  <forname="testForm">            <field property="max" depends="required, maxlength">                <arg0 key="testForm.max"/>                <arg1 key="${var:max}" name="maxlength" resource="false" />                <var>                    <var-name>max</var-name>                    <var-value>8</var-value>                </var>            </field>            <field property="min" depends="required,minlength">                <arg0 key="testForm.min"/>                <arg1 key="${var:min}" name="minlength" resource="false" />                <var>                    <var-name>min</var-name>                    <var-value>4</var-value>                </var>            </field>        </form>
[解决办法]
如果你是不确定要替换的内容

你可以用indexOf(),我不会正则

template.indexOf("${")
自己去找位置然后再用substring()截取或者用replace替换
我喜欢这样做法,容易看得懂
[解决办法]
用MessageFormat
Java code
 MessageFormat form = new MessageFormat("The disk \"{1}\" contains {0}."); double[] filelimits = {0,1,2}; String[] filepart = {"no files","one file","{0,number} files"}; ChoiceFormat fileform = new ChoiceFormat(filelimits, filepart); form.setFormatByArgumentIndex(0, fileform); Object[] testArgs = {new Long(12373), "MyDisk"}; System.out.println(form.format(testArgs)); // output, with different testArgs output: The disk "MyDisk" contains no files. output: The disk "MyDisk" contains one file. output: The disk "MyDisk" contains 1,273 files.