難題_高分吐血求助servlet高手幫忙
各位高手大大:
我有一個在線打開excel,word...的OpenFile servlet,代碼如下:
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package pursue.com.web;
import javax.servlet.*;
import javax.servlet.http.*;
import java.io.*;
import java.util.*;
import pursue.com.util.Globals;
public class Openfile
extends HttpServlet {
private static final String CONTENT_TYPE = "text/html; charset=UTF-8 ";
private String errMsg = "uploadMsg ";
//Initialize global variables
public void init() throws ServletException {
}
//Process the HTTP Get request
public void doGet(HttpServletRequest request, HttpServletResponse response) throws
ServletException, IOException {
HttpSession session = request.getSession();
String filename = request.getParameter( "file_name ");
filename = Globals.RTC_UP_PATH + "/ " + filename;
response.setHeader( "Content-disposition ",
"attachment;filename= " +
filename.replace( '\\ ', '/ ').
substring(filename.lastIndexOf( "/ ")));
String ext=filename.substring(filename.lastIndexOf( ". ")+1);
if(ext.equalsIgnoreCase( "xls ")){
System.out.println( "xlsfile: "+filename);
response.setContentType( "application/vnd.ms-excel ");
}else{
System.out.println( "html: "+filename);
response.setContentType( "text/html ");
}
File doc = new File(filename);
ServletOutputStream out = response.getOutputStream();
FileInputStream fin = new FileInputStream(doc);
int b;
while ( (b = fin.read()) != -1) {
out.write(b);
}
fin.close();
out.close();
//System.out.println( "File is open ! ");
//JLibrary.Foundation.ErrorHandle.logMessage( "File is open ! ");
}
//Process the HTTP Post request
public void doPost(HttpServletRequest request, HttpServletResponse response) throws
ServletException, IOException {
doGet(request, response);
}
//Clean up resources
public void destroy() {
}
public void doFileNotFound(HttpServletRequest request,
HttpServletResponse response) throws Exception {
PrintWriter out = response.getWriter();
out.println( " <html> ");
out.println( " <head> ");
out.println(
" <meta http-equiv=\ "Content-Type\ " content=\ "text/html; charset=UTF-8\ "> ");
out.println( " </head> ");
out.println( " <body bgcolor=\ "#FFCC00\ "> ");
out.println( " <div align=\ "center\ "> ");
out.println( " <p> <img src=\ " " + request.getContextPath() +
"/images/error.gif\ " width=\ "333\ " height=\ "333\ "> </p> ");
out.println( " <p> " + errMsg + " </p> ");
out.println(
" ");
out.println(
" <a href=\ "#\ " onClick=\ "javascript:window.close()\ "> Close Window </a> ");
out.println( " </div> ");
out.println( " </body> ");
out.println( " </html> ");
}
}
-------------------------------------------
在日志裡老報異常
:getOutputStream() has already been called for this response
另外，我在另外一個OpenDoc的servlet中打開word文檔，方式如上，只不過在Open()方法裡加了文件不存在，就調用doFileNotFound()方法,也出現上面的異常.
在google搜索後，大家都說response不能同時使用二進制流和字符流兩種輸入方式..
所以我就把doFileNotFound()中的PrintWriter out = response.getWriter();改成
ServletOutputStream out = response.getOutputStream();全部使用二進制流，依然不行，這個bug前後折磨了我一星期，實在是沒辦法了，求助高手幫忙修改代碼，畫龍點睛....一勞永逸
[解决办法]
o
[解决办法]
private static final String CONTENT_TYPE = "text/html; charset=UTF-8 ";
private String errMsg = "uploadMsg ";
这可不是好习惯
[解决办法]
...........
if(ext.equalsIgnoreCase( "xls ")){
System.out.println( "xlsfile: "+filename);
response.setContentType( "application/vnd.ms-excel ");
}else{
System.out.println( "html: "+filename);
response.setContentType( "text/html ");
}
BufferedInputStream bis =
new BufferedInputStream(
new FileInputStream(new String( filename.getBytes( "GBK "), "ISO8859_1 " )));//chinese
ServletOutputStream bos = response.getOutputStream();
byte[] buff = new byte[2048];
int bytesRead;
while(-1 != (bytesRead = bis.read(buff, 0, buff.length))) {
bos.write(buff,0,bytesRead);
}
bos.flush();
bis.close();
bos.close();
//timeout
response.setStatus(response.SC_OK );
response.flushBuffer();
.......
[解决办法]
先占个位置，再慢慢看
[解决办法]
看了一下你的代码，可能是出现抛出异常后没有关闭ServletOutputStream类
可以尝试一下
File doc = null;
ServletOutputStream out = null;
FileInputStream fin = null;
try{
File doc = new File(filename);
ServletOutputStream out = response.getOutputStream();
FileInputStream fin = new FileInputStream(doc);
int b;
while ( (b = fin.read()) != -1) {
out.write(b);
}
}catch(IOException e)
{
e.printStackTrace();
}
finally{
if(fin != null){
fin.close();
}
if(out != null){
out.close();
}
}
